Deutsche Version |

which is continuously emitted from a sound source.

The total sound energy emitted by a source

per unit time is the sound power

All share as level the same unit of measure: the decibel (dB). The term "sound
level" is commonly substituted for each.As characteristic impedance of air we use the round value Z = 400 N·s/m³ (Pa·s/m).
Then the "sound level", that is the sound pressure level L_{p}and the sound intensity
level
L_{I}is exactly the same as a decibel value.The sound power or acoustic power is the sound energy constantly transfered per second from the
sound source. A sound source has a given constant sound power that does not
change if it is placed in a different room environment.Sound power is a theoretical value that is not measurable. It is calculated and
expressed in watts and as sound power level L_{W} in decibels.A sound source produces sound power and this generates a sound pressure
fluctuation in the air. Sound power is the distance independent cause of this, whereas sound pressure is
the distance-dependent effect. |

At r = 1 meter distance, the sound pressure level (SPL)
of a point source is 11 dB less than its sound power level
(SWL), when Q = 1, the full sphere propagation is given. |

For Q = 1 (full sphere propagation) the sound power level
is equal to sound pressure level or intensity level at the
distance of r = 0.2821 m from the source. |

Sound power or sound power level has nothing to do with the distance from the sound source.Thinking helps: A 100 watt light bulb is emitting constantly the same power.That is really the case - no matter if in 1 m, in 10 m, or even in 100 distance. These emitted watts don't change with distance. They stay in the source. Sound power is the distance independent cause of this, whereas sound
pressure is the distance-dependent effect. |

It is often stated that sound pressure level = SPL, sound intensity level = SIL and sound power level = SWL are not comparable. SPL is measured in pascals = N/m ^{2}, sound intensity is energy measured inW/m ^{2}, and sound power is measured in watts?It is little known that the sound power level (without (!) distance r) is the same as the soundpressure level and the sound intensity levelat full sphere propagation ( Q = 1) at a distancefrom the sound source r = 0.2821 m.1 watt of sound power = 120 dB Sound intensity at r = 0.2821 m: P_{ac} = 1 watt / (4π × r^{2}) = 1 watt, that means (4π × r^{2}) = 1 and r = √(1/4π).10 × log (1/10 ^{−12}) = 120 dBSound pressure level SPL at 0.2821 m = SWL − (20 × log ( r) − 11) = 120 − (20 × log (0.2821) − 11) = 120 dBSo how can they not be comparable? The sound intensity level and the sound pressure level at a distance of 1 meter from the sourcein a free field is 11 dB less than the sound power level of the source. SIL = SPL = SWL − 11 dB or L_{I} = L_{p} = L_{W} − 11 dB.Acoustic impedance of air Z_{0} = 400 Pa×s/m. |

Differentiate: Sound pressure p is a "sound field quantity" and
sound intensity I is a "sound energy quantity". In teachings these
terms are not often separated sharply enough and sometimes
are even set equal. But I ~ p^{2}. |

Important: The sound level should not be confused with sound power level! The dB values in sound pressure levels are always tied to the distance to the sound source, however, the dB values in sound power level have really no relation to the distance from the sound source. Question: How does the sound power decrease with distance"? Answer: "April fool - The sound power does not decrease (drop) with distance from the sound source." However, levels of sound pressure and levels of sound intensity decrease equally with the distance from the sound source. Sound power or sound power level has
nothing (!) to do with the distance from the sound source.Thinking helps: A 100 watt light bulb has in 1 m and in 10 m distance really always the same 100 watts, which is emitted from the lamp all the time. Watts don't change with distance. A frequent question: "Does the sound power depend on distance?" The clear answer is: "No, not really." We consider sound fields in air which are described by the scalar quantity p (sound pressure) and the vector quantity v (sound velocity) as a sound field quantity. |

Sound power and Sound power level |

To use the calculator, simply enter a value. The calculator works in both directions of the ↔ sign. |

Sound power is neither room dependent nor distance dependent. |

**Direct ****conversion of sound pressure to sound intensity**** and vice versa**

Simply enter the value to the left or the right side. The calculator works in both directions of the ↔ sign. |

While the sound pressure level in the air is matched with the sound intensity level when a reference sound characteristic impedance Z_{0} = 400 N·s/m³ is chosen, this is not the case with the distance independent sound power level. |

**The same sound level at distance ***r*** = √(***Q*** / 4**

Geometry |
Directivityfactor Q |
Equal sound levelat distance r |
rdB |

No surface near sound source; able to radiate acoustical energy in all directions; full sphere |
1 | √(1/4π) = 0.2821 m | 11 |

Sound source close to a flat surface; able to radiate acoustical energy to half of a sphere (hemi) |
2 | √(1/2π) = 0.3989 m | 8 |

Close to two adjacent flat surfaces perpendicular to each other; able to radiate to one fourth of a sphere |
4 | √(1/π) = 0.5642 m | 5 |

At a corner; able to radiate acoustical energy to one eighth of a sphere |
8 | √(2/π) = 0.7979 m | 2 |

Full sphere Q = 1 Half sphere Q = 2 Quarter sphere Q = 4 Eighth sphere Q = 8 |

For the practically occurring solid angle, we get the following relationships between the sound power and sound pressure level: For Q = 1 is L_{W} = L_{p} + [20 × log_{10} (r)] + 11 dB (full)For Q = 2 is L_{W} = L_{p} + [20 × log_{10} (r)] + 8 dB (half)For Q = 4 is L_{W} = L_{p} + [20 × log_{10} (r)] + 5 dB (quarter)For Q = 8 is L_{W} = L_{p} + [20 × log_{10} (r)] + 2 dB (eighth)L_{p} = medium sound pressure level at the envelope (hemispherical surface)and for the most frequent case of radiation hemisphere r = 1 m: L_{W} = L_{p} + 8 dB |

Spherical Free Field Sound Propagation, Q = 1 |

The sound pressure in a spherical distance from a source with a known sound power can be expressed as: (1) where p = sound pressure in Pa = N/m^{2}ρ = density of air in kg/m^{3}: 1.2041 kg/m^{3} at 20°Cc = speed of sound in m/s: 343.22 m/s at 20°CP_{ac} = sound power in Wπ = 3.14159r = distance from source in mQ = directivity factor (spherical = 1, half spherical = 2)directivity index - directivity factor - directivity coefficient |

For a spherical sound propagation (Q = 1) at a distance of r = √(1/4π) = 0.2821 mthe decibel value of the sound pressure level is equal to the sound power level. |

Hemispherical Sound Propagation, Q = 2 |

The directivity coefficient Q depends on several parameters − the positionand direction of the source, the room or the surrounding area, etc. The sound pressure level L_{p }can be expressed logarithmic as:L_{p} = 20 log (p/p_{0}) = 20 log ((Q ρ c P_{ac}/(4 π r^{2}))1/2/p_{0})= 20 log (1/r (Q ρ c (2)P_{ac}/(4 π))1/2/p_{0})where L_{p} = sound pressure level in dBp_{0} = 2 × 10^{−5} - reference sound pressure in PaNote: That for every doubling of the distance from the noise source, the sound pressure level L_{p}, will be reduced by 6 decibels. |

For a spherical sound propagation (Q = 2) at a distance of r = √(1/2π) = 0.3989 mthe decibel value of the sound pressure level is equal to the sound power level. |

For point-like sources of sound, we get a spherical surface A. Depending on the arrangement in space spherical segments are to consider: Solid sphere - sound source anywhere in the room, Q = 1Hemisphere - sound source on the ground Q = 2Quarter sphere - sound source on the wall, Q = 4Eighth sphere - sound source in the corner, Q = 8Q = directivity factor and the area A = (4π × r^{2}) / Q |

Sound intensity I = sound power P_{ac} / area ASound power P_{ac} = I × A = I × 4π × r^{2}. |

Sound Pressure Level Calculator |

Consider a source of sound and imagine a sphere with radius r, centered on the source.The sound source outputs a total power P, continuously. The sound intensity I is the sameeverywhere on this surface of a thought sphere, by definition. The intensity I is defined as thepower P per unit area A. The surface area of the sphere is A = 4π × r^{2}, so the sound intensitypassing through each square meter of surface is, by definition: I = P / 4π × r^{2}.We see that sound intensity is inversely proportional to the square of the distance away from the source (1/ r^{2}):I_{2} / I_{1} = r_{1}^{2} / r_{2}^{2}.But sound intensity is proportional to the square of the sound pressure, I ~ p^{2}, so we canwrite: p_{2} / p_{1} = r_{1} / r_{2}. The sound pressure p changes with 1 / r of the distance.So, if we double the distance, we reduce the sound pressure by a ratio of 2 andthe sound intensity by a ratio of 4: in other words, we reduce the sound level by 6 dB. If we increase r by a ratio of 10, we decrease the level by 20 dB. |

When a point source emits sound (or an other form of energy) uniformly in all
directions in a free field, it is spreading over the surface of a sphere of
increasing radius. Full sphere area is 4π × r². Directivity factor Q = 1.The same amount of energy is spreading over a larger and larger area, therefore, the intensity will decrease. The sound source is emitting all the time the acoustic power and stays there. The sound power does not decrease with the distance from the sound source. |

Converting sound power level to sound pressure level |

A noise source radiates power which is measured as the sound power level. |

**W. T. W. CORY: "Relationship between Sound pressure and Sound Power Levels"**

Power is like all energy quantities primarily a calculated value. |

"Sound power" and "sound pressure" are two distinct and commonly confused
characteristics of sound.
They have a cause and effect relationship. Sound power is
the acoustical energy emitted by the sound source, and is an absolute value. It is not affected by the environment.
Sound power levels are connected to the sound source
and are independent of distance. Sound power levels are indicated in decibels.L_{w} = 10×log (P / P_{0}) where:The reference power is 10 ^{−12} watts (W), which is the lowest sound persons of
excellent hearing can discern. Sound power is measured as the total sound power
emitted by a source in all directions in watts (joules per second).Since sound measuring instruments respond to sound pressure the "decibel" is generally associated with sound pressure level (SPL). Sound pressure levels quantify in decibels the strength of given sound sources. Sound pressure levels vary substantially with distance from the source, and also diminish as a result of intervening obstacles and barriers, air absorption, wind and other factors. Sound pressure levels are indicated in decibels. Sound pressure level (SPL) is L_{p} = 20×log (p / p_{0}),
where:The reference sound pressure is p_{0} = 2×10^{−5} Pa = 20 µPa. Sound pressure is a
pressure disturbance in the air whose intensity is influenced not only by the strength
of the source, but also by the surroundings and the distance from the source to the
receiver. Sound pressure is what our ears hear and what sound pressure level
meters (SPL meters) measure. |

Not only take something from this website to enhance your knowledge.Please, also give some feedback to the author to improve the performance. |

back |
Search Engine |
home |